x^(1/2)+y^(1/2)=10

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Solution for x^(1/2)+y^(1/2)=10 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

x^(1/2)+y^(1/2) = 10 // - 10

x^(1/2)+y^(1/2)-10 = 0

1*x^(1/2) = -(y^(1/2)-10) // : 1

x^(1/2) = 10-y^(1/2)

x^(1/2) = 10-y^(1/2) // ^ 2

x = (10-y^(1/2))^2

x = (10-y^(1/2))^2

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